2x^2-5x-700=0

Solution for 2x^2-5x-700=0 equation:

2x^2-5x-700=0

a = 2; b = -5; c = -700;
Δ = b2-4ac
Δ = -52-4·2·(-700)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-75}{2*2}=\frac{-70}{4}
=-17+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+75}{2*2}=\frac{80}{4}
=20
$